Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{6}{ h},\stackrel{-2}{ k})\qquad \qquad radius=\stackrel{12}{ r} \\[2em] [x-6]^2+[y-(-2)]^2=12^2\implies (x-6)^2+(y+2)^2=144[/tex]

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