Answer:
14th term of geometric sequence 7, 28, 112 is 469762048
Step-by-step explanation:
Geometric sequence : 7, 28, 112, .....
First term = a = 7
Common ratio = r =[tex]\frac{a_2}{a_1}=\frac{a_3}{a_2}[/tex]
Common ratio = r =[tex]\frac{28}{7}=\frac{112}{28}=4[/tex]
Formula of nth term =[tex]a_n=ar^{n-1}[/tex]
Substitute n = 14
So,[tex]a_{14}=7(4)^{14-1}[/tex]
[tex]a_{14}=469762048[/tex]
Hence the 14th term of geometric sequence 7, 28, 112 is 469762048
