[tex]\text{Plug in 3 to y and solve:}\\\\4(3)^3-20+9(3)^2+(25 \div5)\\\\4(27)-20+9(3)^2+(25 \div5)\\\\4(27)-20+9(9)+(25 \div5)\\\\4(27)-20+9(9)+5\\\\108-20+81+5\\\\88+86\\\\174\\\\\boxed{\text{A). 174}}[/tex]
Answer:
A) 174
Step-by-step explanation:
I'm assuming 4y3 is 4y³ and 9y2 is 9y²
4×3³-20+9×3²+(25÷5)=
4×3³-20+9×3²+5=
4×27-20+9×9+5=
108-20+81+5=
88+81+5=
169+5=
174
A) 174
