Answer:
[tex]p[H+] = 10.042[/tex]
Explanation:
As we know that
[tex]pKw = pH + pOH[/tex]......eq (1)
we will calculate the pH of OH- and then we will calculate the pH of H+
So p[OH-] [tex]= - log [1.10 * 10^{-4}][/tex]
Solving the right side of the equation, we get
p[OH-]
[tex]= - [-3.958]\\= 3.958[/tex]
Now we know that
[tex]pKw = 14.0[/tex]
Substituting the value of pOH in the above equation, we get -
[tex]14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042[/tex]
