[tex]answer = \sqrt{97} \: units \: \\ solution \\ perpendicular = 4 \\ base = 9 \\ hypotenuse = ?\\ using \: pythagorus \: theorem \\ {h}^{2} = {p}^{2} + {b}^{2} \\ or \: {h}^{2} = {(4)}^{2} + {(9)}^{2} \\ or \: {h}^{2} = \: 16 + 81 \\ or \: {h}^{2} = 97 \\ or \: h = \sqrt{97} \: units \\ hope \: it \: helps[/tex]
