Answer:
[tex] p = \frac {2x}{(2t^2 +m)} [/tex]
Step-by-step explanation:
[tex]p {t}^{2} = \frac {2x - pm}{2} \\
2pt^2 = 2x - pm\\
2pt^2 +pm= 2x \\
p(2t^2 +m) =2x\\\\
\huge\purple {\boxed {p = \frac {2x}{(2t^2 +m)}}}
\\ [/tex]
