Answer:
sin²θ
Step-by-step explanation:
Using the trigonometric identities
sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x
cotx = [tex]\frac{cosx}{sinx}[/tex]
Given
[tex]\frac{1-sin^20}{cot^20}[/tex]
= [tex]\frac{cos^20}{\frac{cos^20}{sin^20} }[/tex]
= cos²θ × [tex]\frac{sin^20}{cos^20}[/tex] ( cancel the cos²θ )
= sin²θ
