Answer:
Infinutely many solutions
Step-by-step explanation:
y = 10x + 2 --------- (1)
y = 8x +2x +2
=> y = 10x + 2---------- (2)
(1) -> 10x -y + 2 = 0
(2) -> 10x -y + 2 = 0
a1=10 ; b1=-1 ; c1 = 2
a2=10 ; b2=-1 ; c2= 2
a1/a2 = 10/10 = 1
b1/b2 = -1/-1 = 1
c1/c2 = 2/2 = 1
therefore, a1/a2 = b1/b2 = c1/c2
Therefore the line coincides and there are infinitely many solutions.
