Answer:Solution for 0.3(y-2)+0.4y=0.3y-0.6 equation:
0.3(y-2)+0.4y=0.3y-0.6
We move all terms to the left:
0.3(y-2)+0.4y-(0.3y-0.6)=0
We add all the numbers together, and all the variables
0.4y+0.3(y-2)-(0.3y-0.6)=0
We multiply parentheses
0.4y+0.3y-(0.3y-0.6)-0.6=0
We get rid of parentheses
0.4y+0.3y-0.3y+0.6-0.6=0
We add all the numbers together, and all the variables
0.4y=0
y=0/0.4
y=0
