The 24th term of the arithmetic sequence where a1 = 8 and a9 = 56 is 146
Arithmetic sequence
- First term, a1 = 8
- Ninth term, a9 = 56
- Common difference = d
a9 = a + 8d
56 = 8 + 8d
56 - 8 = 8d
48 = 8d
divide both sides by 8
d = 48 / 8
d = 6
24th term = a + 23d
= 8 + 23(6)
= 8 + 138
= 146
Therefore, the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56 is 146
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