[tex]\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}\\\\
-------------------------------\\\\
\stackrel{A}{A(x)}=\stackrel{I}{P}(1.02)^{\stackrel{t}{x}}\implies A=P(1+\stackrel{r}{0.02})^x\implies \cfrac{r}{100}=0.02
\\\\\\
r=100\cdot 0.02\implies r=\stackrel{\%}{2}[/tex]
