(h/g)(-4)
[tex] \frac{(-4)-5}{(-4+2)(-4+3)} [/tex]
Plug and chug
Should come out to be -4.5
[tex] \frac{x-5}{(x+2)(x+3)} [/tex]
To find the values not in the domain, you must set each quantity in the denominator equal to zero and solve for x.
x+2=0 x+3=0
x≠-2 x≠-3
If x were either of these numbers, the denominator of the fraction would equal zero, which would give an undefined answer.
