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24-03-2018
Mathematics

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evaluate a/z + bw^2 for a = 21, b=3, w=6, and z=7

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Amphitrite1040 Amphitrite1040

24-03-2018

Hey there!

If [tex]a = 21 , z = 7, b = 3, w = 6 [/tex]

Then our whole problem change

We get: [tex] \frac{21}{7} +(3)(6)^2 \\ \\ \frac{21}{7} = 3 \\ \\ (3)(6)^2 = 108 \\ \\ \\ \\ 3 + 108 = 111 \\ \\ \\ \\ \\ Answer: 111 [/tex]

Good luck on your assignment and enjoy your day!

~[tex]LoveYourselfFirst:)[/tex]

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