Answer:
Square: x= +or - [tex]\sqrt{7}[/tex], Triangle: x= + or - [tex]\sqrt{23}[/tex]
Step-by-step explanation:
For the square
4[tex]x^{2}[/tex]=28
dvide by four:
[tex]x^{2}[/tex]=7
Take the square root of both sides
x= +or - [tex]\sqrt{7}[/tex]
For the Triangle
(1/2) (2x) (2x)=46
2[tex]x^{2}[/tex]=46
Divide by 2
[tex]x^{2}[/tex]=23
x= + or - [tex]\sqrt{23}[/tex]
